非洲牛蛙可以吃吗:惊世之作(绝密买点加逃顶不难),你一旦拥有,天下无敌

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[其他公式] 惊世之作(绝密买点加逃顶不难),你一旦拥有,天下无敌    [复制链接]


  1楼 发表于 2010-8-22 03:24 |只看该作者 |倒序浏览 |打印     .pcb{margin-right:0} 我的原创无未来,请尊重我的劳动成果,不顶不仁呀!!!!!!!!
同学们的支持是我努力的动力
DRAWRECTABS(0,0,30,32,rgb(250,60,80)),color000099;
DRAWRECTABS(0,30,30,33,rgb(250,250,80)),colorred;
DRAWTEXTABS(2,18,'王平家'),colorFFFFFF,LINETHICK1;
DIFF :=EMA(CLOSE,12) - EMA(CLOSE,26);
DEA  :=EMA(DIFF,9);
MACD :=2*(DIFF-DEA);
drawicon(ref(macd,1)=llv(macd,3),l,1),align1;
V1:=EMA(EMA(EMA(CLOSE,8),13),55);
V2:=(REF(HIGH,1)+REF(LOW,1))/2;
V3:=MA(CLOSE,20)+2*STD(CLOSE,20);
DRAWICON(CROSS(V2,V3),HIGH*1.035,10);
DRAWTEXT(CROSS(V2,V3),HIGH*1.02,'绝卖'),COLORblue;
V4:=REF(CLOSE,1);
V5:=SMA(MAX(CLOSE-V4,0),7,1)/SMA(ABS(CLOSE-V4),7,1)*100;
V6:=CROSS(79,V5);
V7:=FILTER(V6,4);
DRAWICON(V7,HIGH*1.035,10);
DRAWTEXT(V7,HIGH*1.02,'绝卖'),COLORgreen;
a1:=ref(c,5)DRAWTEXT((a1 AND all(C>O,2)) OR (a1 AND C>O AND REF(C,1)REF(O,2)),L*0.965,'绝密买点');